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4a^2-29a+30=0
a = 4; b = -29; c = +30;
Δ = b2-4ac
Δ = -292-4·4·30
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-19}{2*4}=\frac{10}{8} =1+1/4 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+19}{2*4}=\frac{48}{8} =6 $
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